How do I the radius of curvature of the loop in meters for
a plane flying 600m/s
experiencing 4g when pulling out of a dive?
The acceleration of an object moving in a circular path is v^2/r, where
v is the speed and r is the radius.
The formula for the centripetal acceleration is a = v^2/r, where v is the
tangential velocity and r is the radius of curvature. In your case, a = 3g
(4g - 1g for the earth's gravity) and v = 600 m/s. All you need to do is
solve for r.
Richard E. Barrans Jr., Ph.D.
PG Research Foundation, Darien, Illinois
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Update: June 2012