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Name: John
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Question:
I am a mathematics teacher and one of my students recently came back from a university interview with the following question he had been asked orally. As far as I can tell he was rejected from a place on the basis of his inability to answer the question. I think he got the question wrong when he presented it to me (English is not his first language) but as always in such cases I could be wrong. I know I cannot figure out an answer and as far as I can tell there is none. Can you help?



Replies:
Find a non-constant function such that [f(x)]^a = af(x).

He was not completely clear whether or not "a" was a variable or a fixed value. He seemed to think it was any old number.

Starting with [f(x)]^a = a*f(x). Take the 'log' of both sides gives: log{[f(x)^a]} = log{a*f(x)}

Using the properties of the 'log' function that: log{x^a} = a* log{x} and
log{a*x} = log {a} +
log{x} gives:

a*log{f(x)} = log{a} + log{f(x)}

Subtracting log{f(x)} from both sides gives:

a*log{f(x)} - log{f(x)} = log{a} . Collecting terms on the left hand side gives:

log{f(x)} * [a -1] = log{a} . Dividing by [a-1] providing a not = 1 gives:

log{f(x)} = (1/[a-1]) * log{a} = log {a}^(1/[a-1])

Taking the exponential of both sides gives:

f(x) = a^(1/[a-1])

This gives f(x) in terms of 'a' provided 'a' not = 1. However, since 'x' does not appear on the right hand side, without knowing some additional relation between 'x' and 'a' those variables have been separated and no solution exists.

Vince Calder


I think the answer they were looking for is f(x) = ln(x).

Tim Mooney


If you take the logarithm of both sides you would get:
f[x]=Exp[ln(a)/(a-1)].
As such, there is no non-constant answer that satisfy this equation.

AK
Ali Khounsary, Ph.D.
Advanced Photon Source
Argonne National Laboratory


If we solve the equation for f(x) by first taking the logorithm of both sides, we get
f(x) = exp{[ln(a)]/(a-1)}.
If a is a constant, then f(x) is a constant. This may be what they were looking for.

Another possibility may be a search for possible values of a. In this problem, the only constant value of a that will work for a non-constant f(x) is a=1.

Kenneth Mellendorf



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