

Photoelectric Effect
Name: Casey
Status: student
Age: 18
Location: N/A
Country: N/A
Date: 20002001
Question:
Details of the photoelectric effect.
I know the general principal behind the photoelectric effect. I
know that when a photon hits an atom, it excites the electrons, and if
the photon has enough eV it will knock the electron out of its
orbital. From Eintein's nobel prize, I know that there is a certain
level at which the electrons in an atom are unleashed and can be
detected. The question I need to be answered is if the electron is only
unleashed when the work function is a certain eV, how do you determine
the range of wavelengths(longest and shortest of the light that is
bombarding a certain material)needed to emit electrons?
Replies:
The light impinging on the metal sample must have more energy than the work
function of the material. The energy of a photon is determined by its
frequency according to the formula
E = h nu
where E is the energy of the photon, h is Planck's constant, and nu is the
frequency of the photon. The wavelength is determined by the frequency by
the formula
lambda = c / nu,
where c is the speed of light and lambda is the wavelength.
This means that a photon with short wavelength has more energy than a photon
with a long wavelength. To cause a material to eject an electron, the
photon must have a wavelength shorter than the one corresponding to an
energy equal to the work function.
Richard E. Barrans Jr., Ph.D.
Assistant Director
PG Research Foundation, Darien, Illinois
Light is composed of a set of "photons". Each photon carries light energy
proportional to the frequency of the light: E=hf/(2*pi). The value of the
constant h is 4.14x10^15 eVs. It is called Planck's constant. An
individual photon must have enough energy to free the electron.
Kenneth Mellendorf
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Update: June 2012

