Temperature and Gravitational Field ```Name: Len W. Status: other Age: 40s Location: N/A Country: N/A Date: 1/29/2004 ``` Question: If, in theory, an object (e.g., an iron ball) reaches the state of having a temperature of absolute zero, does that state alter the degree to which the object will accelerate due to the gravitational influence of another object, e.g., the earth? Replies: There is nothing "mystical" about absolute zero. Gravity operates on the mass of a body according to Newton's law the force, F = GmM/R^2 where m and M are the masses of the objects R is the distance between them and G is the universal gravitational constant. The temperature of either object does not affect the mass, the distance, or the gravitational constant. It is worth noting that for historical reasons, temperature is defined in such a way that the "hotter" the body the larger the number we assign to its temperature. That is completely arbitrary. It would not be any problem to define temperature so that the "hotter" the body THE SMALLER THE NUMBER we assign to its temperature. In that case "absolute zero" just becomes "infinitely cold". And of course it is not possible to attain "infinitely cold". Mother Nature in fact hints that a reciprocal definition might have been a wiser more "natural" choice because in thermodynamic equations very often, if not the majority of the time, "temperature" appears as (1/T). The most essential place this occurs is in the second law. There the change in entropy is defined as dS= dq * (1/T). Vince Calder Nope. Gravity seems to be the most inviolable force in the universe. Mass makes it, and large velocity affects it a little. Otherwise, scientists tend to think in terms of space itself being continually sucked into the hole. Now, maybe that iron ball will spontaneously do a teleportation exchange with an exactly identical iron ball on the other side of the universe, but gravity will be just as satisfied either way... and the iron ball that's here will keep on falling. Maybe all the atoms will become quantum-mechanically locked together, and it will be able to bounce off another such ball without denting or ringing or loosing any energy, but it will still be falling. Not an expert, just a thought-perspective, Jim Swenson The temperature of an object does not affect its gravitational properties except insofar as its mass changes as the temperature changes. You know, I am sure, the famous Einstein equation E = mc^2 = mcc. As the ball cools, the atoms reduce their thermal motion, moving more slowly and so reducing their kinetic energy. Since the energy E of the ball decreases, its mass m must also decrease. This is a very small effect, however, since most of the energy in the object is in its rest mass. The amount of thermal energy in a 1 kg iron ball at room temperature is about 60,000 J. The amount of energy in its rest mass is about 90,000,000,000,000,000 J. This enormous ratio is indicative of the relative power of a nuclear bomb and a chemical bomb. So to a VERY good approximation, the answer to your question is that the temperature does not affect gravitational forces. It is worth mentioning that even if the mass changed by a lot, the acceleration of the iron ball near the earth's surface would not change, as shown by Galileo at the leaning tower of Pisa. This is because the gravitational mass of the ball is exactly proportional (as far as we know) to the inertial mass of the ball. Best, Dick Plano... Click here to return to the Physics Archives

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