Conservation of Momentum and Energy ```Name: Toby Status: student Age: N/A Location: N/A Country: N/A Date: N/A ``` Question: I have been learning about Momentum and Kinetic Energy in science lessons at school, but there is one thing I really cannot get my head around. I have been taught that if an object with a certain momentum (mv) hits another object and all the momentum is conserved, then the new object will have the same momentum, so if the new object had half the mass of the first it would travel at double the speed, e.g. 100kg object travelling at 10m/s hits a 50kg object, so the 50kg object will go at 20m/s (50 * 20 = 100 * 10). What confuses me is when I try to work out the Kinetic Energy of the two objects. If the 100kg object is travelling at 10m/s then it has kinetic energy of 5000J (100/2 * 10^2), but if it hits a 50kg object and all the momentum is conserved then the new object will have kinetic energy of: 50/2 * 20^2 = 10000J. I was under the impression that energy could not be created or destroyed, so how does this 100kg object travelling through a vacuum with 5000J of energy suddenly hit this 50kg object and produce 10000J of energy, where does the extra energy come from? Replies: Hi Toby You are right in questioning the idea that both momentum and energy must be conserved. In an elastic collision, both are conserved. In the example you gave, the total momentum was 1000 kg m/s. That must be the total momentum after the collision. Your example assumes that all the momentum will be transferred to the second object. That will happen only if both objects are the same mass. In your example, the second object is half the mass of the first. So what will happen is the first object will collide with the stationary second object, the second will take off, but the first will not stop, it will just slow down. In that way, the total momentum is conserved, along with total energy. It turns out that the relative speed of two objects after an elastic collision has the same magnitude as before the collision regardless of the masses involved. When a 100 kg mass traveling at 10 m/s collides with a 50 kg stationary mass, the 100 kg object will continue on traveling at 3.33 m/s, while the 50 kg mass takes off at 13.33 m/s. You will see that total momentum and total energy are conserved. Hope this helped. Bob Froehlich Toby, You are quite right, BOTH momentum and energy are conserved. As a result, the first scenario you describe cannot happen, because it would violate the laws of physics. You see, not all of the momentum of the first (initially moving) object will be transferred to the second (initially stationary) object unless both objects have exactly the same mass (and the collision is dead-on). in an elastic collision, both momentum and kinetic energy are conserved. In fact, knowing that makes it possible to figure out exactly what the velocities are after the collision. In an inelastic collision, in which the colliding objects cling together afterwards, kinetic energy is not explicitly conserved. The energy is not lost, however; it becomes thermal energy (higher temperature) in the two objects. No doubt you will learn much more about this as you go along. It is fascinating stuff, and I hope you will enjoy it as much as I do. Richard Barrans Department of Physics and Astronomy University of Wyoming Toby, The second object will not necessarily get all of the momentum. Some may stay in the first object. One such example is when the two objects stick together. Another is when the first object bounces back from that which it hits. Remember that direction counts for momentum. If two objects are traveling in opposite directions, their momentums have opposite signs. As for energy, not all energy is kinetic energy. When objects collide, they can lose kinetic energy by producing sound, by damaging each other, or even by producing heat. Energy is still conserved, but it takes a form we cannot easily measure. Some collisions, called elastic collisions, do not lose any kinetic energy. Such collisions are very quiet, often involving very little contact. If the colliding objects stick together, kinetic energy is always lost. It takes energy to make the objects stick together. This often involves reshaping, such as bending Velcro hooks or flattening a piece of clay. It can involve destruction, such as when two cars have a head-on collision. Dr. Ken Mellendorf Physics Instructor Illinois Central College In perfectly elastic collisions, both kinetic energy and momentum are conserved. Using your example, with a 100kg object traveling at 10m/s, its momentum is 1,000 kg-m/s. If it then hits a 50kg object at rest, the resultant collision must fulfill both of the above constraints (momentum and kinetic energy conserved). The solution you propose to the problem -- that the 50 kg object will go at 20m/s and the 100kg object will be at rest -- does not fulfill the kinetic energy constraint, and so is not correct. That solution meets the conservation of momentum constraint, but not the conservation of kinetic energy constraint. If you solve the equations (m11 * v11 ^2 + m21 * v21 ^2) = (m12 * v12 ^2 + m22 * v22 ^2) and (m11 * v11 + m21 * v21) = (m21 * v21 + m22 * v22) (where the first number is the object, and the second number is the time -- e.g. mass 1 at the start is m11 and mass 1 and the end is m12) You know m1 and m2 (they don't change) and you set v11 and v21. You have two equations and two unknowns (v12 and v22) so you can solve this system directly algebraically. Also, here is a great site that goes over examples: http://hyperphysics.phy-astr.gsu.edu/hbase/colsta.html It has a form to do these calculations for you too! Hope this helps, Burr Zimmerman Click here to return to the Physics Archives

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